WAEC Mathematics Questions And Answers 2021: Get The Objective And Essay Answers For WAEC Mathematics Questions And Answers 2021

WAEC Mathematics Questions And Answers 2021: Students who have applied for WAEC exams have been on the lookout for WAEC Mathematics Questions And Answers 2021. The article below has answers to the both objective and essay questions of WAEC Mathematics Questions And Answers 2021.

by Pooja

Updated Sep 18, 2021

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WAEC Mathematics Questions And Answers 2021: Get The Objective And Essay Answers For WAEC Mathematics Questions And Answers 2021

WAEC Mathematics Questions And Answers 2021

Students have been looking for WAEC Mathematics Questions And Answers 2021 since the WAEC exams have been taking place. The impending exam has piqued the interest of students, who have started hunting for WAEC Mathematics Questions And Answers 2021. The term WAEC stands for West African Examination Council, which is a West African examination and education board mandated by law to conduct tests for West African students. The WAEC normally administers two exams: one in May/June for the SSCE and another in November/December for the WAEC or GCE. Students' intense interest in the WAEC Mathematics Questions And Answers 2021 has resulted in a search for WAEC Mathematics Questions and WAEC Mathematics Answers. For those who are interested, we have compiled a list of objective and theory WAEC Mathematics Questions And Answers 2021 in the article below.

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WAEC Mathematics Objective Answers

The objective WAEC Mathematics Answers and WAEC Mathematics Questions have been in high demand, particularly now that the exam is coming. However, obtaining the objective WAEC Mathematics Questions and Answers 2021 is a difficult task, even though we have obtained WAEC Mathematics Answers. We also learned how the WAEC Mathematics Question Paper will be constructed. The number of Objective Questions is projected to be 50. The WAEC Mathematics Answers to these 50 questions are listed below.

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1. Express, correct to three significant figures, 0.003597.

A. 0.359

B. 0.004

C. 0.00360

D. 0.00359

2. Evaluate: (0.064)^-1/3

A. 5/2

B. 2/5

C. -2/5

D. -5/2

3. Solve: y+1/2 – 2y-1/3 = 4

A. y = 19

B. y = -19

C. y = -29

D. y = 29

4. Simplify, correct to three significant figures, (27.63)^2 – (12.37)^2

A. 614

B. 612

C. 611

D. 610

5. If 7 + y = 4 (mod 8), find the least value of y, 10

A. 11

B. 13

C. 19

D. 21

6. If T = (prime numbers) and

M = (odd numbers) are subsets of

U = (x: 0

A. (4, 6, 8, 10)

B. (1, 4, 6, 8, 10)

C. (1, 2, 4, 6, 8, 10)

D. (1, 2, 3, 5, 7, 8, 9)

7. Evaluate: log9 base 3 – log8 base 2 /log9 base 3

A. -1/3

B. 1/2

C. 1/3

D. -1/2

8. If 23y = 1111two, find the value of y.

A. 4

B. 5

C. 6

D. 7

9. If 6, P and 14 are consecutive terms in an Arithmetic Progression (A.P), find the value of P.

A. 9

B. 10

C. 6

D. 8

10. Evaluate: 2 (SQRT 28) – 3 (SQRT 50) + (SQRT 50)

A. 4 (SQRT 7) – 21 (SQRT 2)

B. 4 (SQRT 7) – 11 (SQRT 2)

C. 4 (SQRT 7) – 9 (SQRT 2)

D. 4 (SQRT 7) + (SQRT 2)

11. If m : n = 2 : 1, evaluate 3m^2 – 2n^2 /m^2 + mn

A. 4/3

B. 5/3

C. 3/4

D. 3/5

12. H varies directly as p and inversely as the square of y. If H = 1, p = 8 and y = 2, find H in terms of p and y

A. H = p /4y^2

B. H = 2p / y^2

C. H = p / 2 y^2

D. H = p / y^2

13. Solve 4x^2 – 16x + 15

A. X = 1 (1/2) or X = -2 (1/2)

B. X = 1 (1/2) or X = 2 (1/2)

C. X = 1 (1/2) or X = -1 (1/2)

D. X = -1 (1/2) or X = -2 (1/2)

14. Evaluate 0.42 divided by 2.5 /0.5 x 2.05, leaving the answer in standard form.

A. 1.639 x 10^2

B. 1.639 x 10^1

C. 1.639 x 10^-1

D. 1.639 x 10^-2

15. Simplify: log6 – 3log3 + 2/3log27.

A. 3log 2

B. Log2

C. Log3

D. 2log3

16. Bala sold an article for 6,900.00 naira and made a profit of 15 percent. Calculate his percentage profit if he had sold for 6600.00.

A. 5 percent

B. 10 percent

C. 12 percent

D. 13 percent

17. If 3p = 4q and 9p = 8q-12, find the value of pq.

A. 12

B. 7

C. -7

D. -12

18. If (0.25)^y = 32, find the value of y.

A. y = -5/2

B. y = -3/2

C. y = 3/2

D. y = 5/2

19. There are 8 boys and 4 girls in a lift. What is the probability that the first person who steps out of the lift will be a boy?

A. 3/4

B. 1/3

C. 2/3

D. 1/4

20. Simplify: x^2 – 5x – 14 / x^2 – 9x + 14

A. X – 7 /x + 7

B. X + 7 /x – 7

C. X – 2 /x + 4

D. X + 2 /x – 2

21. Which of these values would make 3p – 1 /p^2 – p undefined?

A. 1

B. 1/3

C. -1/3

D. -1

22. The total surface area of a solid cylinder is 165 cm2. If the base diameter is 7 cm, calculate its height. (Take pi = 22/7)

A. 7.5 cm

B. 4.5 cm

C. 4.0 cm

D. 2.0 cm

23. If 2^a = SQRT(64) and b/a = 3, evaluate a^2 + b^2.

A. 250

B. 160

C. 90

D. 48

24. In triangle XYZ, line XZ = 32 cm, angle YXZ = 52 degrees and XZY = 90 degrees. Find, correct to the nearest centimeter, line XZ.

A. 31 cm

B. 25 cm

C. 20 cm

D. 13 cm

25. If log 2 base x = 0.3, evaluate log 8 base x.

A. 2.4

B. 1.2

C. 0.9

D. 0.6

26. An arc subtends an angle of 72 degrees at the centre of a circle. Find the length of the arc if the radius of the circle is 3.5 cm. (Take pi = 22/7)

A. 6.6 cm

B. 8.8 cm

C. 4.4 cm

D. 2.2 cm

27. Make b the subject of the relation lb = 1/2(a+b)h

A. ah /2l – h

B. 2l – h/al

C. al/2l – h

D. al/2 – h

29. Eric sold his house through an agent who charged 8 percent commission on the selling price. If Eric received 117,760.00 dollars after the sale, what was the selling price of the house?

A. 130,000.00 dollars

B. 128,000.00 dollars

C. 125,000.000 dollars

D. 120,000.00 dollars

29. Find the angle which an arc of length 22 cm subtends at the centre of a circle of radius 15 cm. (take pi = 22/7)

A. 70 degrees

B. 84 degrees

C. 96 degrees

D. 156 degrees

30. A rectangular board has a length of 15 cm and width x cm. If its sides are doubled, find its new area.

A. 60x cm squared

B. 45x cm squared

C. 30x cm squared

D. 15x cm squared

31. In the diagram, POS and ROT are straight lines. OPQR is a parallelogram, line OS = line OT and angle OST = 50 degrees. Calculate the value of angle OPQ.

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A. 100 degrees

B. 120 degrees

C.140 degrees

D. 160 degrees

32. Factorize completely: (2x + 2y)(x-y) + (2x – 2y)(x + y)

A. 4(x – y)(x + y)

B. 4(x – y)

C. 2(x – y) (x + y)

D. 2(x – y)

33. The interior angles of a polygon are 3x, 2x, 4x, 3x and 6x. Find the size of the smallest angle of the polygon.

A. 80 degrees

B. 60 degrees

C. 40 degrees

D. 30 degrees

34. A box contains 2 white and 3 blue identical balls. If two balls are picked at random from the box, one after the other with replacement, what is the probability that they are of different colours?

A. 2/3

B. 3/5

C. 7/20

D. 12/25

35. Find the equation of a straight line passing through the points (1, -5) and having gradient of ¾.

A. 3x + 4y – 23 = 0

B. 3x + 4y + 23 = 0

C. 3x – 4y + 23 = 0

D. 3x – 4y – 23 = 0

36. The foot of a ladder is 6 m from the base of an electric pole. The top of the ladder rest against the pole at a point 8 m above the ground. How long is the ladder?

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A. 14 m

B. 12 m

C. 10 m

D. 7 m

37. If tan x = 3/4, 0

A. 8/3

B. 3/2

C. 4/3

D. 2/3

38. From the top of a vertical cliff 20 m high, a boat at sea can be sighted 75 m away and on the same horizontal position as the foot of the cliff. Calculate, correct to the nearest

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degree, the angle of depression of the boat from the top of the cliff.

A. 56 degrees

B. 75 degrees

C. 16 degrees

D. 15 degrees

39. In the diagram, O is the centre of the circle of radius 18 cm. If angle ZXY = 70 degrees, calculate the length of arc ZY. (Take pi = 22/7)

A. 11 cm

B. 22 cm

C. 44 cm

D. 80 cm

In the diagram, RT is tangent to the circle at R, angle PQR = 70 degrees, angle QRT = 52 degrees, angle QSR = y and angle PRQ = x. Use the diagram to answer questions 40 and 41

40. Find the value of y.

A. 70 degrees

B. 60 degree

C. 52 degree

D. 18 degree

41. Calculate the value of x

A. 70 degrees

B. 58 degrees

C. 55 degrees

D. 48 degrees

42. Calculate the variance of 2, 4, 7, 8, 9

A. 7.2

B. 6.8

C. 3.5

D. 2.6

43. The fourth term of an Arithmetic Progression (A.P.) is 37 and the first term is -20. Find the common difference.

A. 63

B. 57

C. 19

D. 17

In the diagram, PQ is parallel to RS, angle QFG = 105 degrees and angle FEG = 50 degrees. Use the diagram to answer questions 44 and 45.44. Find the value of m

A. 130 degrees

B. 105 degrees

C. 75 degrees

D. 55 degrees

45. Find the values of n

A. 40 degrees

B. 55 degrees

C. 75 degrees

D. 130 degrees

46. A box contains 5 red, 6 green and 7 yellow pencils of the same size. What is the probability of picking a green pencil at random?

A. 1/6

B. 1/4

C. 1/3

D. 1/2

47. The pie chart represents fruits on display in a grocery shop. If there are 60 oranges on display, how many apples are there?

A. 90

B. 80

C. 70

D. 40

The following are scores obtained by some students in a test.

8 18 10 14 18 11 13 14 17 15 8 16 13

Use this information to answer questions 48 to 50

48. Find the mode of the distribution

A. 18

B. 14

C. 13

D. 8

49. Find the median score.

A. 14.5

B. 14.0

C. 13.5

D. 13.0

50. How many students scored above the mean score?

A. 10

B. 9

C. 8

D. 7

WAEC Mathematics Essay Answers

(1a)

Given A={2,4,6,8,…}

B={3,6,9,12,…}

C={1,2,3,6}

U= {1,2,3,4,5,6,7,8,9,10}

A’ = {1,3,5,7,9}

B’ = {1,2,4,5,7,8,10}

C’ = {4,5,7,8,9,10}

A’nB’nC’ = {5, 7}

(1b)

Cost of each premiere ticket = $18.50

At bulk purchase, cost of each = $80.00/50 = $16.00

Amount saved = $18.50 – $16.00

=$2.50

(2ai)

P = (rk/Q – ms)⅔

P^3/2 = rk/Q – ms

rk/Q = P^3/2 + ms

Q= rk/P^3/2 + ms

(2aii)

When P =3, m=15, s=0.2, k=4 and r=10

Q = rk/p^3/2 + ms = 10(4)/(3)^3/2 + (15)(0.2)

= 40/8.196 = 4.88(1dp)

(2b)

x + 2y/5 = x – 2y

Divide both sides by y

X/y + 2/5 = x/y – 2

Cross multiply

5(x/y) – 10 = x/y + 2

5(x/y) – x/y = 2 + 10

4x/y = 12

X/y = 3

X : y = 3 : 1

(3a)

Diagram

CBD = CDB (base angles and scales D)

BCD+CBD+CDB=180° (Sum of

2CDB+BCD=180°

2CDB+108°=180°

2CDB=180°-108°=72°

CDB=72/2=36°

BDE=90°(Angle in semi circle)

CDE=CDB+BDE

=36°+90

=126

 

(3b)

(Cosx)² – Sinx given

(Sinx)² + Cosx

Using Pythagoras theorem third side of triangle

y²= 1²+√3

y²= 1+ 3=4

y=√4=2

(Cosx)² – sinx/(sinx)² + cosx

 

(1/2)² – √3/2/

(√3/2)² + 1/2 = 1/4 – √3/2 = 1-2√3/4

3/4+1/2 = 3+2/4

=1-2√3/4 * 4/5

=1-2√3/5

(4a)

Total Surface Area = 224πcm²

r:l = 2:5

r/l = 2/5

Cross multiply

2l/2 = 5r/2

L = 5r / 2

Total surface = πrl + πr²

= πr (l + r)

24 π/π = πr (5r/2 + r )/ π

224 = 5r²/2 + r²/1

L.c.m = 2

448 = 5r² + 2r²

448 / 7= 7r²/7

r² = 64

r = √64 = 8cm

L = 5*8/2 = 20cm

(4b)

Volume = 1/2πr²h

= 1/3 * 22/7 * 8 * 8 * 18.33

= 1228.98cm³

L² = h² + r ²

20² = h² + 8²

400 – 64 = h²

h² = 336

h = √ 336

h = 18.33cm

(5a)

Total income = 32+m+25+40+28+45

=170+m

PR(²)=m/170+m = 0.15/1

M=0.15(170+m)

M=25.5+0.15m

0.85m/0.85=25.5/0.85

M=30

(5b)

Total outcome = 170 + 30 = 200

(5c)

PR(even numbers) = 30+40+50/200

=115/200 = 23/40

(7a)

Diagram

Using Pythagoras theorem, l²=48² + 14²

l²=2304 + 196

l²=2500

l=√2500

l=50m

Area of Cone(Curved) =πrl

Area of hemisphere=2πr²

Total area of structure =πrl + 2πr²

=πr(l + 2r)

=22/7 * 14 [50 + 2(14)]

=22/7 * 14 * 78

=3432cm²

~3430cm² (3 S.F)

(7b)

let the percentage of Musa be x

Let the percentage of sesay be y

x + y=100 ——————-1

(x – 5)=2(y – 5)

x – 5=2y – 10

x – 2y=-5 ——————-2

Equ (1) minus equ (2)

y – (-2y)=100 – (-5)

3y=105

y=105/3

y=35

Sesay’s present age is 35years

(8a)

Let Ms Maureen’s Income = Nx

1/4x = shopping mall

1/3x = at an open market

Hence shopping mall and open market = 1/4x + 1/3x

= 3x + 4x/12 = 7/12x

Hence the remaining amount

= X-7/12x = 12x-7x/12 =5x/12

Then 2/5(5x/12) = mechanic workshop

= 2x/12 = x/6

Amount left = N225,000

Total expenses

= 7/12x + X/6 + 225000

= Nx

7x+2x+2,700,000/12 =Nx

9x + 2,700,000 = 12x

2,700,000 = 12x – 9x

2,700,000/3 = 3x/3

X = N900,000

(ii) Amount spent on open market = 1/3X

= 1/3 × 900,000

= N300,000

(8b)

T3 = a + 2d = 4m – 2n

T9 = a + 8d = 2m – 8n

-6d = 4m – 2m – 2n + 8n

-6d = 2m + 6n

-6d/-6 = 2m+6n/-6

d = -m/3 – n

d = -1/3m – n

(9a)

Draw the triangle

(9b)

(i)Using cosine formulae

q² = x² + y² – 2xycosQ

q² = 9² + 5² – 2×9×5cos90°

q² = 81 + 25 – 90 × 0

q² = 106

q = square root 106

q = 10.30 = 10km/h

Distance = 10 × 2 = 20km

(ii)

Using sine formula

y/sin Y = q/sin Q

5/sin Y = 10.30/sin 90°

Sin Y = 5 × sin90°/10.30

Sin Y = 5 × 1/10.30

Sin Y = 0.4854

Y = sin‐¹(0.4854), Y = 29.04

Bearing of cyclist X from y

= 90° + 19.96°

= 109.96° = 110°

(9c)

Speed = 20/4, average speed = 5km/h

(12a)

BCD=ABC=40°(alternate D)

DDE=2*BCD(

DDE = 2*40 = 80°

OD3=OED(base

ODE + OED + DOE= 180°(sum of

2ODE+DOE=180°

2ODE+80°=180

2ODE+180=180

2ODE+100°

ODE+100/2=50°

(12bi)

Digram

(12bii)

Area of parallelogram = absin

=5*7*sin 125°

=35*sin 55°

=35*0.8192

=28.67

=28.7cm²(1dp)

(12c)

Given x=1/2(1-√2)

2x²-2x=2[1/2(1-√2]²-2(1/2(1-√2)}

=2[1-2√2+2/4]-(1-√2)

=(3-2√2/2)-(1-√2)

=3-2√2-2+2√2/2=1/2

Note: The above questions are presumably WAEC Mathematics repeated questions and answers, rather than 2021 WAEC Mathematics questions and answers. These are just practise questions. Do not fall prey to internet scammers that promise you access to a live question paper before the exam in exchange for money. The WAEC General Maths Examination will be written on Monday,20th September.
 

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WAEC Mathematics Questions And Answers 2021: FAQs

1. Where can I get WAEC Mathematics Question And Answers 2021?

You can get WAEC Mathematics Question And Answers 2021 here once they are updated.

2. What is WAEC ?

WAEC is the acronym for West African Examination council which is an examination and education board in West Africa established by the law to conduct exams for West African Students.

3. When did WAEC 2021 Start?

WAEC 2021 has started from 16th August 2021.

4. What is the two exams conducted by WAEC?

SSCE and WAEC or GCE are the two exam conducted by WAEC.

5. When is SSCE exam conducted by WAEC?

WASSCE - conducted in May - June is called the SSCE.

6. When is GCE exam conducted by WAEC?

WASSCE - conducted in November - December is called the WAEC or GCE.

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